Ages Model 1 — The “Together” Time Jump

Problems on Ages · 25 min

Aptitude · Problems on Ages · Model 1

Both people jump together, so the gap is your ruler

Model 1 gives you two ratios of the same two people at two moments, with the same number of years added to each of them. Because the jump is symmetrical the age gap is common to both ratios, and that turns a pair of simultaneous equations into one division.

Watch two ratios get scaled to a common gap
Scale both ratios until their difference in units is the same. Then one unit means the same number of years in both facts, and the shift in units prices it directly.

01 The idea

A three-year senior is still three years older in the office

Vijay is 18 and in his first year of B.Tech. Radha is 21 and in her fourth. Ten years later they both work at the same company; Vijay is 28 and Radha is 31. Their years of study, their salaries and their job titles all changed. The three-year gap did not, because the ten years were added to both of them.

That is the shape of every Model 1 question. You are handed two ratios of the same pair at two different moments, and the shift between those moments applies to both people equally. "Ten years ago the ratio was 3 : 1" and "ten years from now it will be 2 : 1" are two photographs of one family taken twenty years apart.

The naive route is to set the first ratio as 3x and x, add twenty to each, cross-multiply and solve. That always works and it is worth being able to do cold. But it throws away the fact that makes the model easy: both ratios describe the same gap in years, so once their gaps agree in units, one unit means the same thing in both.

Here is the family this lesson uses. A mother and daughter were in the ratio 3 : 1 ten years ago, and the mother will be twice as old ten years from now. They are 70 and 30 today, a gap of 40 years. Ten years ago they were 60 and 20 — gap 40. Ten years hence they are 80 and 40 — gap 40. Three ratios, one gap.

In a symmetrical time jump the age gap is the only quantity shared by both ratios. Make the two ratios agree on how many units that gap is worth, and the arithmetic is finished in one division.
Symmetrical jumpThe same number of years added to both people. Every Model 1 question is one of these, which is exactly why the gap survives and can be used as a ruler. Contrast Model 3, where one age goes back while the other goes forward.
Gap in unitsThe difference between the two numbers of a ratio. In 3 : 1 the gap is 2 units; in 2 : 1 it is 1 unit. Two ratios of the same pair must be rescaled until these agree, because in years the gap is one fixed number.
Shift in unitsHow far one person's share moves between the two rescaled ratios. From 3 : 1 to 4 : 2 the mother's share goes 3 → 4, a shift of 1 unit — and that one unit is the whole twenty-year jump.

02 Worked example

The long way, once, so the shortcut makes sense

Ten years ago the ages of a mother and daughter were in the ratio 3 : 1. Ten years from now the mother's age will be twice the daughter's. Find their present ages. This is the bracket method in full. Section 03 does the same question in four lines.

1
Anchor the unknown at the earlier momentBoth given facts sit away from today, so anchoring at the earlier one keeps every shift positive and every sign easy.10 years ago: mother = 3x, daughter = x
2
Measure the jump between the two momentsFrom ten years ago to ten years hence is twenty years, not ten. This is the single most common slip in the model, and it is a reading slip rather than an algebra one.−10 to +10 → jump = 20 years
3
Add the jump to both, in brackets, and write the second ratioThe same twenty years lands on each of them. "Twice as old" is the ratio 2 : 1, written against the shifted ages.(3x + 20) / (x + 20) = 2 / 1
4
Cross-multiply and solve for the unitOne equation, one unknown. The x terms nearly cancel, which is the signature of a well-set Model 1 question.3x + 20 = 2(x + 20) → 3x + 20 = 2x + 40 → x = 20
5
Price the ages, then walk them to the presentx = 20 gives the ages ten years ago. Add ten to each for today, and check the gap at both moments before you commit.10 years ago: 60 and 20  →  today: 70 and 30  (gap 40 ✓)  →  in 10 years: 80 and 40 = 2 : 1 ✓

Look at what x turned out to be: 20 years, which is exactly the size of the jump. That is not a coincidence. In 3 : 1 the gap is 2 units and in 2 : 1 it is 1 unit, so rescaling the second to 4 : 2 makes both gaps 2 units — and then the mother's share moves from 3 units to 4 units, one unit, across twenty years. The shortcut in section 03 reads that off without ever writing an equation.

03 The method

The unit-shift shortcut in four lines

This is the method to use in the exam. It works whenever the jump is symmetrical, which in Model 1 is always, and it replaces the whole equation with one division.

Both ratios must agree on the gap. Scale ratio one by L / |a − b| and ratio two by L / |c − d|, where L is the LCM of the two gaps. Then 1 unit = (elapsed years) / (shift in units), and every age in the question is a whole number of units.
Two habits that make it safe. First, the elapsed years run from the earlier moment to the later one — "10 years ago" to "10 years hence" is 20, not 10. Second, check the direction: going forward the ratio must move towards 1 : 1, so 3 : 1 can become 2 : 1 later but never the reverse. If your ratios move the wrong way, you have swapped the two moments.
LineWhat you doOn 3 : 1 then, 2 : 1 ten years hence
1Read the gap in units from each ratio3 − 1 = 2 units; 2 − 1 = 1 unit
2Scale both to the LCM of those gaps3 : 1 stays; 2 : 1 becomes 4 : 2 (gap 2)
3Read the shift in the first person's share3 units → 4 units, shift = 1 unit
4Divide the elapsed years by the shift20 years / 1 unit = 20 years per unit
5Price the ages at the earlier moment3 × 20 = 60 and 1 × 20 = 20
6Add the years to reach the present60 + 10 = 70 and 20 + 10 = 30
7Check the gap at both moments60 − 20 = 40 and 80 − 40 = 40 ✓

05 Cheat sheet

Model 1 on one page

The first four rows are the shortcut. The last three are the errors that turn a thirty-second question into a wrong answer.

SituationWhat to doOn mother 70, daughter 30
Two ratios, same gap in units1 unit = years / shift7 : 3 now, 2 : 1 in 10 yr → scale to 4 : 2, shift 1, unit 10
Two ratios, different gapsscale to the LCM of the gaps first3 : 1 (gap 2) with 2 : 1 (gap 1) → 4 : 2
Ratio plus a gap in yearsgap in units = gap in years3 : 1 ten years ago, gap 40 → 2 units = 40, unit 20
Ratio plus a sum of agestotal units = total years7 : 3 today, sum 100 → 10 units = 100, unit 10
"10 years ago" to "10 years hence"jump is 20, not 1060 and 20 → 80 and 40
Ratio moving away from 1 : 1 over timeimpossible2 : 1 now cannot be 3 : 1 later
Answer found at the earlier momentnot the answer yet60 and 20 are past ages; add 10
The gap is the rulerBoth ratios describe one fixed number of years of difference. That is the only quantity they share, so matching the gap in units is what makes their units comparable.
Measure the jump, do not assume itPast-to-future questions double the number you first think of. Write the two moments on a line as −10 and +10 and read the distance off, every time.
Direction is a free checkForward in time the ratio must approach 1 : 1. If the later ratio is further from 1 : 1, you have read the two moments in the wrong order — catch it before you solve.

06 Where & why

Where Model 1 shows up

This is the most-set ages model in Indian placement papers, and it is set as a speed question with four widely spaced options.

TCS Digital · Amazon aptitude
Two ratios, one of them in the past

The house pattern. The unit-shift shortcut answers it in the time it takes to write the two gaps, which is what the section timing assumes you will do.

Bank PO · SSC CGL
Ratio plus a gap or a sum

One ratio and one absolute number — a difference of 40 years, or a total of 100. Both reduce to "how many units is that number worth", which is the same division.

Data sufficiency sets
Two statements, each a ratio

Each ratio alone is one equation in two unknowns and never sufficient. Together they are, unless they are the same ratio at different moments — the case the setter hides in one option.

Multi-person variants
C is 13 years younger than B, D is 8 younger than A

Solve the two-person Model 1 core first, then the extra people are one subtraction each. The extra names add reading time, not difficulty.

If you can look at "3 : 1 ten years ago, 2 : 1 ten years hence" and say "gaps 2 and 1, scale to 4 : 2, shift 1 unit over 20 years, so a unit is 20" out loud, this model is finished.

07 Interview questions

What gets asked about symmetrical jumps

Ten in escalating order — the setup, the shortcut, why the shortcut is valid, and the two traps that account for most wrong answers.

What makes a question a Model 1 question?
Both people move by the same number of years between the two given facts. That symmetry is what keeps the age gap constant across both ratios, and the whole method depends on it. If one person goes back while the other goes forward, it is Model 3 and the gap trick does not apply.
Solve it: the ratio is 3 : 1 today and will be 2 : 1 in fifteen years.
3 : 1 has a gap of 2 units and 2 : 1 has a gap of 1, so rescale 2 : 1 to 4 : 2. The first person's share moves from 3 units to 4 units, a shift of 1 unit, over 15 years — so a unit is 15 years and the ages are 45 and 15.
Why is it legitimate to scale one ratio and not the other?
Because a ratio carries no size information; 2 : 1 and 4 : 2 are the same statement about the same two people. What you are doing is choosing the unit so that the fixed age gap is the same number of units in both facts, which is the only way to compare them directly.
A question says ten years ago and ten years hence. What is the jump?
Twenty years. Put the two moments on a line at −10 and +10 and read the distance off rather than reusing the number in the question. Using 10 here is probably the single most common error in the model and the wrong answer is always in the options.
Can the ratio 2 : 1 become 3 : 1 later?
No. Going forward in time a ratio always moves towards 1 : 1, because the fixed gap becomes a smaller share of both ages as they grow. A later ratio further from 1 : 1 means you have swapped the two moments, and noticing it costs a second and saves the question.
You are given one ratio and the difference in years. Is that enough?
Yes, and it is faster than the two-ratio case. The gap in units equals the gap in years directly: 3 : 1 with a 40-year difference gives 2 units = 40, so a unit is 20 and the ages are 60 and 20. The same works with a sum — total units equal the total in years.
What if the two given ratios are the same ratio at different times?
Then they are not sufficient, and the shortcut says so cleanly: after scaling, the shift in units is zero and you cannot divide by it. Physically, a ratio that has not moved in ten years belongs to two people of equal age, so it is 1 : 1 and there is nothing left to find.
Compare the shortcut with just writing 3x and x and cross-multiplying.
The equation method always works and needs no direction check, so it is the safer fallback. The shortcut is roughly three times faster and less error-prone on the arithmetic, but it needs the two gaps rescaled correctly. Learn the equation first, then use the shortcut under time pressure.
A question adds C and D, defined relative to A and B. Does the method change?
No. Solve the two-person Model 1 core for A and B, then apply the extra sentences one at a time — each is a single addition or subtraction. The extra names are there to consume reading time, and the arithmetic behind them is trivial.
When would you actually use this outside an exam?
The specific manoeuvre, essentially never. What transfers is the idea of finding the invariant — the quantity two snapshots share — and measuring everything against it. That is the same reasoning as tracking a fixed cost while a margin moves, and it is worth having as a reflex.

08 Practice problems

Six symmetrical jumps

Try each one with the unit-shift shortcut first, then confirm with the equation. Two of them have unequal gaps in units, so the scaling step is not optional.

Same gap, straight shift

Easy
At present the ratio of the ages of Maya and Chhaya is 6 : 5. Fifteen years from now the ratio will be 9 : 8. Find Maya's present age.
Follow-up
Both ratios already have a 1-unit gap, so no scaling is needed and the shortcut runs in one line. The trap is reading 9 : 8 as three units of shift rather than checking the gaps first.
Show the hint
Maya's share goes from 6 units to 9 units, and those 3 units cover the fifteen years.

A ratio and a multiple

Easy
The ratio of A's present age to B's present age is 5 : 3. Ten years ago A was exactly 5 times as old as B. Find A's present age.
Follow-up
"5 times as old" has to be rewritten as the ratio 5 : 1 before it is comparable with 5 : 3, and the gaps are 2 and 4 — so this one needs the scaling step.
Show the hint
Scale 5 : 1 up to 10 : 2 so both facts carry a 2-unit gap, then read the shift.

Two extra people bolted on

Medium
The ratio of the ages of A and B eight years ago was 5 : 7, and eight years from now it will be 9 : 11. C's present age is 13 years less than B's, and D's present age is 8 years less than A's. Find the sum of the present ages of C and D.
Follow-up
The extra names are reading load, not difficulty — but the question never asks for A or B, so a student who stops at the Model 1 core has not answered it. Solve the core, then apply two subtractions.
Show the hint
Both given ratios have a 2-unit gap, and the shift covers a sixteen-year jump.

Gaps that do not match

Medium
Four years ago the ratio of the ages of P and Q was 4 : 5. Eight years from now the ratio of their ages will be 11 : 13. Find the sum of their present ages.
Follow-up
The gaps are 1 unit and 2 units, so the shortcut fails until you rescale — and it is the earlier ratio that has to be doubled, not the later one. Getting that the wrong way round produces a plausible wrong answer.
Show the hint
Double 4 : 5 to 8 : 10 so both facts carry a 2-unit gap, then compare 8 with 11.

The answer is a ratio, not an age

Medium
Ten years ago Karishma's age was one-third of Babita's age. Fourteen years from now the ratio of their ages will be 5 : 9. Find the ratio of their present ages.
Follow-up
"One-third of" has to become 1 : 3 first, and then the gaps are 2 and 4. The question then asks for a ratio at a third moment, so you must convert back to ages and re-form the ratio rather than reusing either given one.
Show the hint
Scale 1 : 3 to 2 : 6 so both gaps are 4 units, then price one unit across the twenty-four-year jump.

When one side is a group

Hard
The present age of a father equals the sum of the ages of his four children. After ten years the sum of the children's ages will be 1.6 times the father's age. Find the father's present age.
Follow-up
The jump is still symmetrical in the sense that ten years pass for everybody — but the father gains 10 years while the sum of four children's ages gains 40. Treating a group total like one person is the error the question exists to punish, and it is the exact idea Model 5 is built on.
Show the hint
Let the father be F and the children's total be C, with C = F today. In ten years compare C + 40 with 1.6(F + 10).