Model 1 — Finding the Ratio

Ratio and Proportion · 20 min

Aptitude · Ratio and Proportion · Model 1

When two multiples are equal, the numbers swap

The whole of Model 1 is one move. Given 3A = 5B, the ratio A : B is 5 : 3 — each letter takes the other one’s coefficient. Extend it to three equal multiples and the same idea gives you a three-term ratio with no algebra at all.

Set the coefficients and watch the ratio fall out
2A = 3B = 4C gives A : B : C = 6 : 4 : 3. Hide each coefficient in turn and multiply the two you can still see.

01 The idea

One equation, read backwards

“Three times A’s load is exactly equal to five times B’s load.” That is 3A = 5B, and the ratio it hides is A : B = 5 : 3. Divide both sides by 3 and by B and you get A/B = 5/3, which is the ratio. In an exam you skip the algebra: the number next to B moves to A, the number next to A moves to B.

The direction feels wrong the first time. A has the smaller coefficient and the larger share. That is exactly right, because a smaller multiplier reaching the same total needs a bigger quantity to work on. Use it as your check — whichever letter carries the smaller coefficient is the bigger quantity.

The same reasoning handles percentages and fractions without any new rule. “40% of S equals 60% of P” is 40S = 60P once the per-cent signs cancel, so S : P = 60 : 40 = 3 : 2. And “K’s payment is 2/7 of J’s” is even more direct: the first name named takes the top number and the second takes the bottom, so K : J = 2 : 7.

Three equal multiples are the hard version, and they are worth learning properly because they are set often. For 2A = 3B = 4C, call the common value k. Then A = k/2, B = k/3 and C = k/4. Choosing k as the LCM of 2, 3 and 4 clears every fraction at once: k = 12 gives 6, 4 and 3. There is a shortcut that skips even that, and section 02 builds it.

In pA = qB the coefficients trade places: A : B = q : p. The letter with the smaller coefficient is the larger quantity.
The swappA = qB ⇒ A : B = q : p. The single move that Model 1 is built on, and the one that has to become automatic.
The common value kFor pA = qB = rC, the number all three products equal. Setting k to the LCM of the coefficients makes all three quantities whole numbers.
Hide and multiplyFor three equal multiples, each quantity’s share is the product of the other two coefficients: A : B : C = qr : pr : pq. No LCM and no division.

02 Worked example

2A = 3B = 4C, worked two ways

One equation runs the whole lesson. Two times A’s hidden logs equals three times B’s equals four times C’s. Find A : B : C, and confirm that the pair A : B inside your answer agrees with the two-term rule.

1
Start with the pair inside itTake just 2A = 3B and swap the coefficients. This is the two-term rule, and it gives you something to check the final answer against.2A = 3B  ⇒  A : B = 3 : 2
2
Name the common valueAll three products are the same number. Call it k, and each quantity is k divided by its own coefficient.2A = 3B = 4C = k  ⇒  A = k/2, B = k/3, C = k/4
3
Choose k as the LCM to clear the fractionsAny k works, but the LCM of 2, 3 and 4 is the one that makes all three quantities whole. That is 12.k = 12  ⇒  A = 6, B = 4, C = 3  ⇒  A : B : C = 6 : 4 : 3
4
The shortcut: hide and multiplyCover each coefficient in turn and multiply the two still visible. No LCM, no division, and it works for any three coefficients.A = 3×4 = 12, B = 2×4 = 8, C = 2×3 = 6  ⇒  12 : 8 : 6 = 6 : 4 : 3 ✓
5
Substitute back, and check the pairPut 6, 4 and 3 into the original equation. All three products must be equal, and A : B must reduce to the 3 : 2 from step one.2×6 = 3×4 = 4×3 = 12 ✓    6 : 4 = 3 : 2 ✓

The two routes to 6 : 4 : 3 are worth doing once each. The LCM route explains why the answer is what it is; the hide-and-multiply route is what you use under time pressure. And the final substitution is not optional — a swap performed in the wrong direction produces 4 : 6 : 12-style answers that look plausible and fail the check instantly.

03 The method

Every sentence shape this model uses

Four phrasings, one underlying equation each. The right-hand column is the answer you should be able to write without a pen.

pA = qB ⇒ A : B = q : p. For three, pA = qB = rC ⇒ A : B : C = qr : pr : pq, then simplify. Percentages and fractions need no new rule: cancel the per-cent signs, or read the numerator and denominator straight onto the two names.
The direction check costs two seconds and saves the question. After the swap, the letter with the smaller coefficient must have the larger share. In 3A = 5B, A carries the 3 and ends up with 5 parts — larger, as required. If your answer has the big coefficient sitting on the big share, you swapped in the wrong direction. For the three-term case, substitute all three back; the products have to agree.
SentenceAs an equationRatio
3 times A equals 5 times B3A = 5BA : B = 5 : 3
K’s pay is 2/7 of J’s payK = (2/7)JK : J = 2 : 7
40% of S equals 60% of P40S = 60PS : P = 3 : 2
Half of A equals a third of BA/2 = B/3A : B = 2 : 3
2A = 3B = 4Cthree equal products6 : 4 : 3
3x = 4y = 5zLCM 6020 : 15 : 12
Reading pA = qB as A : B = p : qthe wrong directiongives 3 : 5 instead of 5 : 3

05 Cheat sheet

Model 1 on one page

One rule, one shortcut, one check, and the four sentence shapes that trigger them.

CaseRuleExample
Two equal multiplespA = qB ⇒ q : p3A = 5B → 5 : 3
Percentage equalitycancel the % and swap40%S = 60%P → 3 : 2
Fractional sharenumerator : denominatorK = (2/7)J → 2 : 7
Equal fractionsdenominators, in placeA/2 = B/3 → 2 : 3
Three equal multiplesqr : pr : pq2A=3B=4C → 6 : 4 : 3
Direction checksmall coefficient, big shareA has the 2 and gets 6 parts
Swapping the wrong waythe only real error here3A = 5B is not 3 : 5
Multiplying swaps, dividing does not2A = 3B gives 3 : 2, but A/2 = B/3 gives 2 : 3. In the first the numbers multiply the letters; in the second they divide them. That is the same distinction the translation toolkit makes, and it is the one worth over-learning.
The three-term case needs no LCMHide each coefficient and multiply the other two. For 2, 3, 4 that is 12 : 8 : 6, which simplifies to 6 : 4 : 3. The LCM route gives the identical answer and takes longer.
Substitution is the free checkPut your answer back in. All the products have to land on the same number — 12, for 6 : 4 : 3 with coefficients 2, 3, 4. Nothing else in this model can catch a reversed swap.

06 Where & why

Where this shows up

Model 1 is line one of hundreds of questions. Its value is that it is almost free — once the swap is automatic, the whole model costs no time at all.

TCS NQT · Infosys
“If 3A = 5B, find A : B”

Asked directly, worth a mark, done in three seconds. The only failure mode is swapping the wrong way, which the direction check eliminates.

SSC CGL Tier 2
Three equal multiples

“If 3x = 4y = 5z, find x : y : z” gives 20 : 15 : 12. Hide-and-multiply beats the LCM route once the numbers stop being small.

Direct value substitution
“If x : y = 8 : 9, find (5x − 4y) : (3x + 2y)”

Once you have the ratio you may substitute x = 8 and y = 9 literally, because the expression is itself a ratio and the scale cancels. That gives 4 : 42 = 2 : 21.

Every later model
The entry step

Models 2 to 9 all begin with a clean integer ratio. Model 1 is how you get one out of whatever sentence the paper actually gave you.

Two habits finish this model. Swap, then check the direction against the coefficients. For three terms, hide and multiply, then substitute back. Neither check costs more than a few seconds, and between them they remove the only errors this model has.

07 Interview questions

What gets asked

Ten. The first is the whole model; the rest are the variations a setter reaches for once the first one is too easy.

If 3A = 5B, what is A : B?
5 : 3. Divide both sides by 3B to get A/B = 5/3, so the coefficients trade places. Check the direction: A carries the smaller coefficient and gets the larger share, which is right, because a smaller multiplier needs a bigger quantity to reach the same product.
Why do the coefficients swap?
Because both products are the same number. If 3A and 5B are equal, and 5 is larger than 3, then B must be smaller than A to compensate. Algebraically, dividing 3A = 5B by 3B gives A/B = 5/3 directly.
“40% of S equals 60% of P.” Find S : P.
3 : 2. Cancel the per-cent signs to get 40S = 60P, swap for S : P = 60 : 40, then simplify. Sanity check: a smaller percentage of S matches a larger percentage of P, so S has to be the bigger quantity.
“K’s payment is 2/7 of J’s.” Find K : J.
2 : 7. Here nothing swaps — the first name named takes the numerator and the second takes the denominator, because K = (2/7)J rearranges to K/J = 2/7. Compare with the percentage case, where the numbers do swap.
A/2 = B/3 gives what ratio, and why is it not 3 : 2?
2 : 3. The numbers here are dividing the letters, not multiplying them, so the denominators stay under their own letters. Setting both sides to 1 makes it obvious: A = 2 and B = 3.
If 2A = 3B = 4C, find A : B : C.
6 : 4 : 3. Hide each coefficient and multiply the other two: 3×4 = 12, 2×4 = 8, 2×3 = 6, giving 12 : 8 : 6, which simplifies to 6 : 4 : 3. Substituting back, all three products equal 12.
Explain the hide-and-multiply shortcut.
For pA = qB = rC, each quantity is the common value divided by its own coefficient, so the shares are proportional to 1/p, 1/q, 1/r. Multiplying all three by pqr turns that into qr : pr : pq — which is exactly “cover your own coefficient and multiply the others”.
If 3x = 4y = 5z, find x : y : z.
20 : 15 : 12. The LCM of 3, 4 and 5 is 60, so x = 60/3 = 20, y = 60/4 = 15 and z = 60/5 = 12. Hide-and-multiply gives 20 : 15 : 12 directly, since 4×5, 3×5 and 3×4 are 20, 15 and 12.
If A : B = 8 : 9, find (5A − 4B) : (3A + 2B).
2 : 21. Because the target is itself a ratio, the scale cancels, so you may substitute A = 8 and B = 9 literally: (40 − 36) : (24 + 18) = 4 : 42 = 2 : 21. There is no need to carry an x through the algebra.
When can you substitute the ratio terms as if they were the actual values?
Whenever the quantity asked for is itself a ratio, or a fraction of two homogeneous expressions — then the unknown scale factor cancels top and bottom. You cannot do it when the question wants an absolute value, such as a share in rupees; for that you need one real number as well as the ratio.

08 Practice problems

Six on finding the ratio

The first two should take seconds. The middle three are the substitution questions that make this model worth marks, and the last one is the three-term case pushed further than a paper usually goes.

Two swaps

Easy
Find the ratio in each case: (a) 3A = 5B, find A : B. (b) K = (2/7)J, find K : J.
Follow-up
One sentence swaps the numbers and one does not. Doing them back to back is the only reliable way to stop conflating the two.
Show the hint
In one of them the number multiplies its letter, and in the other it divides it.

Percentages cancel

Easy
If 40% of S is equal to 60% of P, find S : P. Then say which of S and P is larger, without using your answer.
Follow-up
The second half is the direction check made explicit. A smaller percentage matching a larger one tells you which quantity is bigger before you compute anything.
Show the hint
Drop both per-cent signs first; they divide out.

Substitute the ratio directly

Medium
If x : y = 8 : 9, find (5x − 4y) : (3x + 2y). Then verify your answer by taking x = 16 and y = 18 instead.
Follow-up
The verification is the point: the answer must not change when you scale x and y, and seeing that happen is what licenses the substitution shortcut in the first place.
Show the hint
Both numerator and denominator are homogeneous in x and y, so the scale factor cancels.

A ratio inside a ratio

Medium
If A/5 = B/7 = C/8, find (A + B + C) : A, and find (A + C) : B.
Follow-up
Two different combinations from one chain, so you have to read the ratio as three actual numbers rather than a formula. The denominators are the ratio here, with no swapping.
Show the hint
Set A = 5, B = 7 and C = 8, then read both answers straight off.

The hidden coefficient

Medium
If x/(2y) = 6/7, find (x − y) : (x + y).
Follow-up
The 2 is buried in the denominator, so the ratio x : y is not 6 : 7. Clearing it first is the whole question; everything after that is arithmetic.
Show the hint
Cross-multiply to get 7x = 12y before you decide what x : y is.

Three multiples, and what they add up to

Hard
If 3x = 4y = 5z, (a) find x : y : z. (b) Find (x + y + z) : z. (c) If in addition x − z = 32, find x, y and z. (d) Explain why the answer to (b) did not need the information in (c).
Follow-up
Part (d) is the real question. A ratio fixes the shape of an answer and an absolute value fixes its scale — and any quantity that is itself a ratio needs only the shape. That distinction is what separates the questions you can answer instantly from the ones that need one more given.
Show the hint
For (a) take the LCM of 3, 4 and 5, or hide and multiply. For (c) find what one part is worth.