Aptitude · Percentages · Model 2
Down 20% then up 20% leaves you down 4%
Two changes in a row never add, because the second acts on what the first left. The formula A + B + AB/100 is the whole model, and the product term is exactly what the naive sum forgets.
Set two changes and watch the product term appear →01 The idea
The second change acts on a different number
An income falls 20% and then rises 20%. It feels like it should be back where it started, and it is not — it is down 4%. The fall took 20% of the original; the rise gave 20% of the smaller figure that was left. Different bases, so they cannot cancel.
Work it in multipliers. Down 20% is × 0.8, up 20% is × 1.2, and 0.8 × 1.2 = 0.96. So you keep 96% of what you had — a 4% loss. That is the whole computation, and it generalises to any number of changes because multipliers chain.
Expanding the product gives the standard formula: for changes of A% and B%, the net change is A + B + AB/100, with the signs carried. For −20 and +20 that is −20 + 20 − 400/100 = −4%. The first two terms are the naive sum; the third is the correction the naive sum omits.
One special case is worth knowing outright. Equal and opposite changes of x% always leave a loss of x²/100 per cent — 4% for 20%, 9% for 30%, 1% for 10%. It is always a loss, whichever order you apply them in, and never zero.
02 Worked example
Income down 20%, then up 20%
The case everyone gets wrong first. A person’s income decreases by 20% and then increases by 20%. What is the net change?
The lost 4% is exactly the 20% that was not restored: the rise gave back 16 where the fall had taken 20. Note also that reversing the order gives the same answer — up 20% to 120, then down 20% to 96. Multipliers commute, so the order of successive changes never affects the final value.
03 The method
The formula, and the consumption question built on it
One formula covers every successive-change question. The second box is the model’s other half, and it is the same idea read backwards.
| Changes | Naive sum | True net |
|---|---|---|
| −20% then +20% | 0% | −4% |
| −30% then +30% | 0% | −9% |
| +15% then −20% | −5% | −8% |
| +20% then −30% | −10% | −16% |
| +25% then −20% | +5% | 0% |
| Price −20% | — | consumption may rise 25% |
| Price −50% | — | consumption may rise 100% |
05 Cheat sheet
Model 2 on one page
The formula, the two special cases, and the consumption rule.
| Case | Route | Worked |
|---|---|---|
| Two changes | A + B + AB/100 | −20, +20 → −4% |
| As multipliers | (1+A/100)(1+B/100) − 1 | 0.8 × 1.2 = 0.96 |
| Equal and opposite x% | loss of x²/100 % | 20% → 4% loss |
| Price falls R%, consumption | R/(100−R) × 100 | 20% → 25% |
| Income and expenditure both +x% | savings also +x% | no calculation needed |
| Order of the changes | irrelevant | multipliers commute |
| Adding the percentages | always wrong | misses AB/100 |
06 Where & why
Where Model 2 shows up
One of the most heavily set percentage models, because the intuitive answer is wrong and is always in the options.
“Income up 20%, expenditure up 15% — find the change in savings.” Work in 100s and it is four short lines.
“Price falls 10% — by how much may consumption rise?” The answer is 11.11%, and 10% is the trap option.
Successive discounts use A + B + AB/100 with both signs negative. A markup then a discount is the same formula with mixed signs.
Percentage changes over successive years multiply. This is also why compound interest is a power rather than a product.
07 Interview questions
What gets asked
Ten, and the first two are the misconception the model exists to break.
An income falls 20% and then rises 20%. What is the net change?
Give the general formula.
What happens with equal and opposite changes of x%?
Does the order of the two changes matter?
Petrol falls 10% in price. By how much may consumption rise with no change in expenditure?
And if the price falls 50%?
An income rises 20% and expenditure rises 15%, with 75% originally spent. What happens to savings?
Is there a shortcut when income and expenditure change by the same percentage?
What two changes leave a quantity exactly unchanged?
How does this connect to successive discounts?
08 Practice problems
Six successive changes
Take the starting value as 100 wherever the answer is a percentage. Write both multipliers before calculating.